Question

If the length of a `53 cm` spring increases to `87 cm` when a `1 kg` weight is hanging from it, what is the spring's constant?

Answer 1

28.8 N/m

Explanation:

`Δx = 87cm - 53cm`

`Δx = 34cm`

`F = mg`

`F = 1kg * 9.8m/s^2`

`F = 9.8N`

`F = k * Δx`

`k = F / (Δx)`

`k = (9.8N) / (34 cm)`

`k = 0.288 N/(cm)`

`k = 28.8 N/m`