Question

Question #fb84b

Answer 1

Good catch,the book should have included the solution species `"Sn"^{2+}`.

Explanation:

The iron metal is not in solution and thus should still be left out. Thus, properly,

`E=E^0-{RT}/{6F}ln({["Sn"^{4+}]^3}/{["Sn"^{2+}]^3["Fe"^{3+}]^2})`

Note that the tin ion concentrations can be rendered as a ratio between oxidized and reduced solution species:

`E=E^0-{RT}/{6F}ln[ { ( (["Sn"^{4+}])/(["Sn"^{2+}]))^3}/{["Fe"^{3+}]^2}]`