What is #64^(1/3)# ?

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Answer 1 · 2017-07-26T03:39:22

#64^(1/3) = 4#

#64^(1/3) = root3(64)#

When finding roots of integers it is often helpful to express the integer as its prime factors.

#64 = 2xx2xx2xx2xx2xx2#

#:. root3(64) =root3(2xx2xx2xx2xx2xx2)#

We can now take each triple through the #root# one time.

#:. root3(64) = 2xx2 = 4#

Hence, #64^(1/3) = 4#

Answer 2 · 2017-07-26T11:41:17

#4#

#64^(1/3)#

#= (4xx4xx4)^(1/3)#

#= 4^((3xx1/3))#

#=4^1#

#=4#