Question #5bb41
1 Answer
Explanation:
For starters, you need a balanced chemical equation to go by. Since you didn't provide one, I'll assume that this is the reaction you're working with
#"C"_ ((s)) + "O"_ (2(g)) -> "CO"_ (2(g))#
Notice that for every
Since you know that
This implies that in order to produce
#120 color(red)(cancel(color(black)("g CO"_2))) * overbrace("32.0 g O"_2/(44.01color(red)(cancel(color(black)("g CO"_2)))))^(color(blue)("the equivalent of a 1:1 mole ratio")) = color(darkgreen)(ul(color(black)("87 g O"_2)))#
The answer is rounded to two sig figs.