Question

How do you differentiate `x+y=xy`?

Answer 1

`dy/dx=(y-1)/(1-x)`

Explanation:

`"differentiate "color(blue)"implicitly with respect to x"`

`"differentiate " xy" using the "color(blue)"product rule"`

`rArr1+dy/dx=xdy/dx+y`

`rArrdy/dx(1-x)=y-1`

`rArrdy/dx=(y-1)/(1-x)`