Question

Question #00338

Answer 1

`0.0286M`

Explanation:

We're asked to find the molarity of the `"HCl"` in the gastric juice with some given titration data.

First, let's write the balanced chemical equation for this neutralization reaction:

`"NaOH"(aq) + "HCl"(aq) rarr "NaCl"(aq) + "H"_2"O"(l)`

• Here's a hint we can use only in the special case of one-to-one molar ratios:

`M_1V_1 = M_2V_2`

where

• `M_1` and `M_2` are the molarities of the two solutions

• `V_1` and `V_2` are the volumes of the two solutions

We have:

• `M_1 = 0.0249M` (`"NaOH"`)

• `V_1 = 28.7` `"mL"`

• `M_2 = ?` (`"HCl"`)

• `V_2 = 25.00` `"mL"`

Plugging in known values, we have

`(0.0249M)(28.7color(white)(l)"mL") = (M_2)(25.00color(white)(l)"mL")`

`M_2 = color(red)(ul(0.0286M`