How do you divide #(25x^2-30x+12) div (5x-3)#?
2 Answers
Aug 1, 2017
#=5x-3#
#=21#
Explanation:
Give -
#(25x^2-30x+12) -:(5x-3)#
#
#=5x-3#
#=21#
Aug 1, 2017
Explanation:
#"one way is to use the divisor as a factor in the numerator"#
#"consider the numerator"#
#color(red)(5x)(5x-3)color(magenta)(+15x)-30x+12#
#=color(red)(5x)(5x-3)color(red)(-3)(5x-3)color(magenta)(-9)+12#
#=color(red)(5x)(5x-3)color(red)(-3)(5x-3)+3#
#"quotient "=color(red)(5x-3)," remainder "=3#
#rArr(25x^2-30x+12)/(5x-3)=5x-3+3/(5x-3)#