Question

How do you write the point slope form of an equation for a lint that passes through (-4,-3), m=1?

Answer 1

`y+3=x+4`

Explanation:

`"the equation of a line in "color(blue)"point-slope form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))`

`"where m represents the slope and " (x_1,y_1)" a point"`
`"on the line"`

`"here "m=1" and " (x_1,y_1)=(-4,-3)`

`y-(-3)=1(x-(-4))`

`rArry+3=x+4larrcolor(red)" in point-slope form"`