Question

How do you differentiate `y=(lnx)^4`?

Answer 1

`dy/dx=(4(lnx)^3)/x`

Explanation:

`"differentiate using the "color(blue)"chain rule"`

`"given "y=f(g(x))" then"`

`dy/dx=f'(g(x))xxg'(x)larr" chain rule"`

`y=(lnx)^4`

`rArrdy/dx=4(lnx)^3xxd/dx(lnx)`

`color(white)(rArrdy/dx)=(4(lnx)^3)/x`