How do you write the point-slope form of an equation of the line that passes through the given point (-2,5), (9,5)?

1 Answer
Aug 4, 2017

See a solution process below:

Explanation:

First, we need to determine the slope of the line. The slope can be found by using the formula: #m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))#

Where #m# is the slope and (#color(blue)(x_1, y_1)#) and (#color(red)(x_2, y_2)#) are the two points on the line.

Substituting the values from the points in the problem gives:

#m = (color(red)(5) - color(blue)(5))/(color(red)(9) - color(blue)(-2)) = (color(red)(5) - color(blue)(5))/(color(red)(9) + color(blue)(2)) = 0/11 = 0#

The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #(color(red)(x_1, y_1))# is a point the line passes through.

We can substitute the slope we calculated and the values from the first point in the problem line to give the formal point-slope form for the equation of the line represented by the two points in the problem.

#(y - color(red)(5)) = color(blue)(0)(x - color(red)(-2))#

#(y - color(red)(5)) = color(blue)(0)(x + color(red)(2))#

We can also substitute the slope we calculated and the values from the second point in the problem line to give the formal point-slope form for the equation of the line represented by the two points in the problem.

#(y - color(red)(5)) = color(blue)(0)(x - color(red)(9))#

If necessary, we can also reduce both these equations down to:

#y - color(red)(5) = color(blue)(0)#

Or

#y = 5#