What is the polar form of #( -34,99 )#?
1 Answer
Explanation:
We're asked to find the polar coordinate of a given Cartesian coordinate.
To do this, we can use the the equations
#ul(r^2 = x^2 + y^2#
#ul(theta = arctan(y/x)#
for the polar coordinate
Here,
#x = -34#
#y = 99#
So we have
#r^2 = (-34)^2 + 99^2#
#r = sqrt((-34)^2 + 99^2) = color(red)(ulbar(|stackrel(" ")(" "104.676" ")|)#
The argument
#theta = arctan(99/(-34)) = ul(-1.240)# OR#ul(1.902# (both in radians)
Arctangent calculations will give two answers, each a half-circle (
Here, the
Thus,
#color(red)(ulbar(|stackrel(" ")(" "theta = 1.902" ")|)#
So the polar coordinate is
#color(blue)((104.676, 1.902)#