What is the polar form of #( -34,99 )#?

1 Answer
Aug 4, 2017

#(104.676, 1.902)#

Explanation:

We're asked to find the polar coordinate of a given Cartesian coordinate.

To do this, we can use the the equations

#ul(r^2 = x^2 + y^2#

#ul(theta = arctan(y/x)#

for the polar coordinate #(r,theta)#

Here,

#x = -34#

#y = 99#

So we have

#r^2 = (-34)^2 + 99^2#

#r = sqrt((-34)^2 + 99^2) = color(red)(ulbar(|stackrel(" ")(" "104.676" ")|)#

The argument #theta# will be

#theta = arctan(99/(-34)) = ul(-1.240)# OR #ul(1.902# (both in radians)

Arctangent calculations will give two answers, each a half-circle (#pi#/#180^"o"#) apart, so be sure to know which one it is.

Here, the #x#-coordinate is negative and the #y#-coordinate is positive, so the angle must be in quadrant II (i.i. the angle must be betwen #pi/2# and #pi#).

Thus,

#color(red)(ulbar(|stackrel(" ")(" "theta = 1.902" ")|)#

So the polar coordinate is

#color(blue)((104.676, 1.902)#