The quadratic formula states:
For #color(red)(a)x^2 + color(blue)(b)x + color(green)(c) = 0#, the values of #x# which are the solutions to the equation are given by:
#x = (-color(blue)(b) +- sqrt(color(blue)(b)^2 - (4color(red)(a)color(green)(c))))/(2 * color(red)(a))#
Substituting:
#color(red)(1)# for #color(red)(a)#
#color(blue)(-8)# for #color(blue)(b)#
#color(green)(12)# for #color(green)(c)# gives:
#x = (-color(blue)((-8)) +- sqrt(color(blue)((-8))^2 - (4 * color(red)(1) * color(green)(12))))/(2 * color(red)(1))#
#x = (color(blue)(8) +- sqrt(color(blue)(64) - 48))/2#
#x = (color(blue)(8) +- sqrt(16))/2#
#x = (color(blue)(8) - 4)/2# and #x = (color(blue)(8) + 4)/2#
#x = 4/2# and #x = 12/2#
#x = 2# and #x = 6#
