How do you graph #y=(x-4)^2 # by plotting points?

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Answer 1 · 2017-08-08T02:56:45

Refer to the explanation for the process.

Graph:

#y=(x-4)^2#

This is a quadratic equation in vertex form: #y=a(x-h)^2+k#, where #k=0#, and the graph will be a parabola.

Choose values for #x# and solve for #y#. These will be your points.

#x=0,##y=16#

#x=1,##y=9#

#x=2,##y=4#

#x=3,##y=1#

#x=4,##y=0#

#x=5,##y=1#

#x=6,##y=4#

#x=7,##y=9#

#x=8,##y=16#

There are 9 points. Plot them on a grid and sketch a parabola through the points.

graph{y=(x-4)^2 [-14.71, 17.32, -3.1, 12.92]}