Question

How do you find the value of `sec theta` given `tan theta=3/2` and in quadrant III?

Answer 1

`-sqrt13/2.`

Explanation:

`sec^2theta=1+tan^2theta=1+(3/2)^2=1+9/4=13/4.`

`sectheta=+-sqrt13/2.`

Since, `theta` lies in `Q_(III), sectheta=-sqrt13/2.`