Voltage input in a circuit is V = 300sin(omegat)V=300sin(ωt) with current I = 100cos(omegat)I=100cos(ωt). Average power loss in the circuit is??
1 Answer
Aug 9, 2017
There is no real power dissipated by the impedance.
Explanation:
Please observe that
this means the current is phase shifted
We can write the voltage and current as magnitude and phase:
Solving the impedance equation:
for Z:
This means that the impedance is an ideal 3 Farad capacitor.
A purely reactive impedance consumes no power, because it returns all of the energy on negative part of the cycle, that was introduced on the positive part of the cycle.