How does permanganate ion oxidize oxalate dianion to give carbon dioxide, and #Mn^(2+)#? Given #0.1467*g# of #"sodium oxalate"#, what was the concentration with respect to #"permanganate"# if #28.85*mL# were required for equivalence?
1 Answer
Well, we needs a redox equation............
I gets approx.
Explanation:
Permanganate ion is reduced to COLOURLESS
The abrupt colour change acts as the indicator for this reaction........
And oxalate ion is oxidized to give 2 equiv of carbon dioxide.......take that climate!
Are these individual redox equations balanced with respect to mass and charge? Do not trust my arithmetic........
And we adds the redox equation so that electrons, conceptual particles, do not appear in the final equation. And thus
The which is balanced with respect to mass and charge, and thus a reasonable representation of reality.........
And thus there were
And so we can calculate