Question

What is the boiling point of an aqueous solution of `LiBr` that is `0.527*mol*kg^-1` with respect to the salt?

Answer 1

This site lists `K_B`, the ebullioscopic constant of water, as `0.512*""^@C*kg*mol^-1`.....

Explanation:

We know that in aqueous solution the lithium bromide salt speciates to its constituent ions.........

`LiBr(s) stackrel(H_2O)rarrLi^+ + Br^(-)`

And `DeltaT_"boiling point elevation"=ixx"molal conc."xxK_B`

And `i=2` because of the speciation of the ionic solute......

`DeltaT=2xx0.527*mol*kg^-1xx0.512*kg*mol^-1*""^@C`

`=0.540` `""^@C`

And thus the observed boiling point of the solution should be `100.540` `""^@C`.