Question

What is the molar concentration of `"38% w/w HCl"`?

Answer 1

`"Concentration HCl"=12.7*mol*L^-1`

Explanation:

How did I get that figure? Well we need a value for the density of `HCl`; this site reports that the density of `38%` `HCl` is `rho=1.189*g*mL`. Now we need this value if we are to approach the question......

`"Concentration"="Molarity"="Moles of solute (mol)"/"Volume of solution (L)"`

And thus.....`"molarity"` using a volume of `1*mL`....

`=((38%xx1.189*g*mL^-1xx1*mL)/(35.45*g*mol^-1))/(1xx10^-3*L)=12.7*mol*L^-1`.