How do I solve #4(x-3)-(x-5)=0#?

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Answer 1 · 2017-08-14T20:51:06

#x=7/3#

Refer to the explanation for the process.

Solve:

#4(x-3)-(x-5)=0#

Expand.

#4x-12-x+5=0#

Simplify.

#3x-7=0#

Add #7# to both sides.

#3x=7#

Divide both sides by #3#.

#x=7/3#