Question

How do you graph `y=3.00x+23`?

Answer 1

See a solution process below:

Explanation:

To graph a linear equation we need to plot two points on the line and then draw a line through them.

For `x = 0`

`y = (3.00 xx 0) + 23`

`y = 0 + 23`

`y = 23` or `(0, 23)`

For `x = 1`

`y = (3.00 xx 1) + 23`

`y = 3.00 + 23`

`y = 26` or `(1, 26)`

Next, we can plot the two points on the grid:

graph{(x^2+(y-23)^2-0.251)((x-1)^2+(y-26)^2-0.25)=0 [-35, 35, -5, 30]}

Now, we can draw the line through the two points:

graph{(x^2+(y-23)^2-0.251)((x-1)^2+(y-26)^2-0.25)(y-3x-23)=0 [-35, 35, -5, 30]}