Question #86795

1 Answer
Aug 17, 2017

The kinetic energy should become one ninth of the initial one.

Explanation:

The initial kinetic energy will be:
#K=1/2mv^2#
as the velocity becomes #v_1=1/3v# we get a new kinetic energy:
#K_1=1/2mv_1^2=1/2m(1/3v)^2=1/2m1/9v^2=1/9(1/2mv^2)=1/9K#