Question

How do you graph `-2x-3y=-12` using intercepts?

Answer 1

See a solution process below:

Explanation:

x-intercept

To find the `x`-intercept set `y` to `0` and solve for `x`:

`-2x - 3y = -12` becomes:

`-2x - (3 xx 0) = -12`

`-2x - 0 = -12`

`-2x = -12`

`(-2x)/color(red)(-2) = (-12)/color(red)(-2)`

`x = 6` or `(6, 0)`

y-intercept

To find the `y`-intercept set `x` to `0` and solve for `y`:

`-2x - 3y = -12` becomes:

`(-2 xx 0) - 3y = -12`

`0 - 3y = -12`

`-3y = -12`

`(-3y)/color(red)(-3) = (-12)/color(red)(-3)`

`y = 4` or `(0, 4)`

Next, plot these two points.

graph{((x-6)^2+y^2-0.025)(x^2+(y-4)^2-0.025)=0}

Now, draw a line through the two points to graph the line of the equation:

graph{(-2x-3y+12)((x-6)^2+y^2-0.025)(x^2+(y-4)^2-0.025)=0}