How do you find the roots, real and imaginary, of #y= -2x^2 - 5x + 6 - (x-5)^2 # using the quadratic formula?

Question

1239 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-18T12:03:19

You gotta write it in standard form...

first, multiply out:

#y = -2x^2 - 5x + 6 -( x^2- 10x + 25)#
# = -2x^2 - 5x + 6 - x^2 + 10x - 25#

...now, collect the terms

#= -3x^2+5x -19#

...and now you have your coefficients a, b, and c:

a = -3, b = 5, c = -19

...that you can plug into the quadratic formula:

#x = (-b +- sqrt(b^2 - 4ac))/(2a)#

...and I'll bet you can take it from here.

GOOD LUCK