How do you solve #6/61=12/h#?

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Answer 1 · 2017-08-19T21:27:24

See a solution process below:

First, because the are two pure fractions on each side of the equation we can "flip" the fractions:

#61/6 = h/12#

Now, multiply each side of the equation by #color(red)(12)# to solve for #h# while keeping the equation balanced:

#color(red)(12) xx 61/6 = color(red)(12) xx h/12#

#cancel(color(red)(12))2 xx 61/color(red)(cancel(color(black)(6))) = cancel(color(red)(12)) xx h/color(red)(cancel(color(black)(12)))#

#122 = h#

#h = 122#