The force applied against an object moving horizontally on a linear path is described by #F(x)=x^2-3x +5#. By how much does the object's kinetic energy change as the object moves from # x in [ 0 , 2 ]#?

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Answer 1 · 2017-08-21T12:03:21

The change in kinetic energy is #=6.67J#

The change in kinetic energy is equal to the work

#DeltaKE=W#

#F(x)=x^2-3x+5#

#DeltaW=F*Deltax#

#W=int_0^2(x^2-3x+5)dx=[x^3/3-3/2x^2+5x]_0^2#

#=(8/3-6+10)-(0)#

#=(4+8/3)#

#=20/3=6.67J#