Question

Can Someone help me please? Thanks!

Answer 1

We gots `stackrel(+VII)"Cl"` in `"perchlorate........."`

Explanation:

The sum of the oxidation numbers is equal to the charge on the ion; here we gots `ClO_4^-`. The oxidation state of oxygen is usually `-II` and it is here.....

And thus `Cl_"oxidation number"+4xx(-2)=-1`

It does not take too much arithmetic to see that `Cl` has an oxidation number of `+VII`.

What about for `BrO_4^-`, `ClO_3^(-)` ion, and `ClO^-`? Please put the answer in the comments.

And what is the oxidation number of aluminum?