How do you differentiate #f(x)= (3x^2-4 )/ (7x +1 )# using the quotient rule?
1 Answer
Aug 22, 2017
Explanation:
#"given " f(x)=(g(x))/(h(x))" then"#
#f'(x)=(h(x)g'(x)-g(x)h'(x))/(h(x))^2larr" quotient rule"#
#g(x)=3x^2-4rArrg'(x)=6x#
#h(x)=7x+1rArrh'(x)=7#
#rArrf'(x)=(6x(7x+1)-7(3x^2-4))/(7x+1)^2#
#color(white)(rArrf'(x))=(21x^2+6x+28)/(7x+1)^2#
