Simplify #lnx^(1/2)+lnx^(1/3)#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Aug 24, 2017 #lnx^(1/2)+lnx^(1/3)=5/6lnx# Explanation: We can use here #lna^m=mlna# Hence, #lnx^(1/2)+lnx^(1/3)# = #1/2lnx+1/3lnx# = #lnx(1/2+1/3)# = #5/6lnx# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1507 views around the world You can reuse this answer Creative Commons License