How do you find the quotient of #(r^2-12r+11)div(r-1)#?

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Answer 1 · 2017-08-24T13:07:40

See a solution process below:

We can rewrite this expression as:

#(r^2 - 12r + 11)/(r - 1)#

We can factor the numerator as:

#((r - 11)(r - 1))/(r - 1)#

We can now cancel common terms in the numerator and denominator to give:

#((r - 11)color(red)(cancel(color(black)((r - 1)))))/color(red)(cancel(color(black)(r - 1))) =>#

#r - 11# where #(r - 1) != 0# or #r != 1#