How do you solve #4(x-1)^2-3=25#?
1 Answer
Aug 27, 2017
Explanation:
#"isolate "(x-1)^2" on the left side"#
#"add 3 to both sides"#
#4(x-1)^2cancel(-3)cancel(+3)=25+3#
#rArr4(x-1)^2=28#
#"divide both sides by 4"#
#cancel(4)/cancel(4)(x-1)^2=28/4#
#rArr(x-1)^2=7#
#color(blue)"take the square root of both sides"#
#sqrt((x-1)^2)=+-sqrt7larr" note plus or minus"#
#rArrx-1=+-sqrt7#
#"add 1 to both sides"#
#xcancel(-1)cancel(+1)=+-sqrt7+1#
#rArrx=1+-sqrt7#
