How do you find the vertical, horizontal or slant asymptotes for #y= cot (x/2)#?

1 Answer
Aug 28, 2017

You know that #cot(theta) = 1/tan(theta) = cos(theta)/sin(theta)#

and you know that this will be undefined wherever the value of the denominator is zero - because you can't divide by zero.

#sin(theta) = 0# when #theta = 0,pi,2pi,3pi...#

so, if #x/2 = theta#, then, we have a vertical asymptote when

#x/2 = 0,pi,2pi,3pi...#

multiply the left side (and every item in the sequence on the right side) by 2 gives us:

#x = 0, 2pi, 4pi, 6pi...#