How do you factor #6x^3-5x^2+x#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer EZ as pi Sep 1, 2017 #x(3x-1)(2x-1)# Explanation: Take out a common factor of #x# #x(6x^2 -5x+1)# Find factors of #6# which add to #5# #x(3x-1)(2x-1)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 2558 views around the world You can reuse this answer Creative Commons License