Question

At constant pressure, how should the volume of a gas enclosed in a piston evolve when the absolute temperature is DOUBLED?

Answer 1

The volume should double......why? Well, old `"Charles Law"` says......

Explanation:

........`VpropT`, at constant pressure...and `T` is quoted in `"absolute temperature....."`

And thus `V=kT`, `k` is a so-called `"constant of proportionality"` that we must ourselves define......

And so `V/T=k`, but this should hold under ALL scenarios where pressure and amount of gas are constant.....

And thus `V_1/T_1=V_2/T_2`, pressure, and quantity of gas constant.

And so we solve for `V_2=(V_1xxT_2)/T_1`, and clearly this has units of volume as required.........

And finally we solve the problem, given that `T_2=2T_1`

`V_2=(V_1xx2cancelT_1)/cancelT_1=2V_1`. Capisce?