How do you find the inverse of f(x)=x^2-2f(x)=x22 from x<=0x0 and graph both f and f^-1f1?

1 Answer
Sep 5, 2017

See below.

Explanation:

To find the inverse of a function, you can switch the xx and yy variables and solve for yy.

y=x^2 - 2y=x22

x = y^2 - 2x=y22 -> switch variables

x+2 = y^2x+2=y2

y = +- sqrt (x+2)y=±x+2

However, since f(x)f(x) is restricted to x<=0x0, f^(-1)(x)f1(x) will be restricted to y<=0y0. We only take the negative result above.

f^(-1)(x) = -sqrt(x+2)f1(x)=x+2

To graph f(x)f(x), simply graph the parabola but keep only the negative xx-values.

![desmos.com](useruploads.socratic.org)

To graph f^(-1)(x)f1(x), graph sqrtxx, then translate it 22 units left and reflect it over the xx-axis.

![desmos.com](useruploads.socratic.org)

If two functions are inverses, they should be reflections of each other over the line y=xy=x. The graph below confirms that they are indeed inverses.

![desmos.com](useruploads.socratic.org)