Question

How do you solve `1/ 5y - 2/ 3= 6`?

Answer 1

`y=100/3`

Explanation:

First, let's eliminate the denominators on the left side of the equation. To do this, we will multiply the equation by 15.

`1/5y - 2/3 = 6 ->`

`15(1/5y - 2/3 = 6) ->`

`3y - 10 = 90`

Now we can solve for y.

`3y - 10 = 90 ->`

`3y = 100 ->`

`y = 100/3`

Answer 2

`y=100/3`

Explanation:

Given -

`1/5 y-2/3=6`

Add `2/3` to the both side

`1/5y -2/3+2/3=6 +2/3`
`1/5y cancel(-2/3) cancel(+2/3)=6 +2/3`
`1/5y=6+2/3`
`1/5y=(18+2)/3=20/3`
`1/5 y= 20/3`
Mutiply both sides by 5
`1/5y xx 5=20/30xx5`
`1/cancel5y xx cancel5=20/30xx5=100/3`
`y=100/3`