How do you solve #1/ 5y - 2/ 3= 6#?
2 Answers
Sep 6, 2017
Explanation:
First, let's eliminate the denominators on the left side of the equation. To do this, we will multiply the equation by 15.
Now we can solve for y.
Sep 6, 2017
#y=100/3#
Explanation:
Given -
#1/5 y-2/3=6#
Add
#1/5y -2/3+2/3=6 +2/3#
#1/5y cancel(-2/3) cancel(+2/3)=6 +2/3#
#1/5y=6+2/3#
#1/5y=(18+2)/3=20/3#
#1/5 y= 20/3#
Mutiply both sides by 5
#1/5y xx 5=20/30xx5#
#1/cancel5y xx cancel5=20/30xx5=100/3#
#y=100/3#