Question

A 75.0 mL steel reaction vessel is filled with oxygen gas (O2) until the pressure reads 145 atm at 22C. How many moles of oxygen are in the container?

Answer 1

Assuming ideality.....then approx. half a mole.......of `O_2`..

Explanation:

We assume ideality, and thus `n=(PV)/(RT)`

`=(145*atmxx75.0*mLxx10^-3*L*mL^-1)/(0.0821*(L*atm)/(K*mol)xx295.15*K)`

`=??*mol`