How do you find the domain and range of #y= 4/(x+1)#?

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Answer 1 · 2017-09-11T14:23:01

The domain is #x in RR-{-1}#
The range is #y in RR -{0}#

The denominator must de #!=0#

#x+1!=0#, #=>#, #x!=-1#

The domain is #x in RR-{-1}#

To find the range, we proceed as follows

#y=4/(x+1)#

#y(x+1)=4#

#x+1=4/y#

#x=4/y-1=(4-y)/y#

For the same reason as above,

#y!=0#

The range is #y in RR -{0}#

graph{4/(x+1) [-36.54, 36.54, -18.28, 18.27]}