Question #abe4b

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Answer 1 · 2017-09-11T16:06:10

#t=-1+ln7-2ln3#

If I interpret the question correctly:

#3e xx 3e^(3t) = 7e^(2t)#

#9e^(3t+1) = 7e^(2t)#

Taking the logarithm of both sides and using the properties of logarithms:

#ln(9e^(3t+1)) = ln(7e^(2t))#

#ln9+ln(e^(3t+1)) = ln7 +ln(e^(2t))#

#ln9+3t+1 = ln7 +2t#

#t=-1+ln7-2ln3#