Question #95e4b
2 Answers
This is
Simple harmonic motion (I know u know this ),
For simple harmonic motion Equation is written as
k=Force constant,
AS ,
k=
k=
So substitute here get lambda
And ,
frequency=
c is speed of light=
Intensity=[Power]/area
Intensity is inversely proportional to
So,
Intensity=
So,
divide both of them i.e as 45 and ant 90,
Given equation represents a transverse wave with general equation as
y(x,t)=Asin ((2pi)/lambda)(x-vt) .......(1)
whereA is maximum amplitude,lambda is wavelength andv wave velocity. Also-vt implies velocity in+x direction
It also represents Traveling Wave Solution for an ideal string.
it's equivalent form can be written as
y(x,t)=Asin 2pi(x/lambda-t/T) ........(2)
whereT is time period and related to frequency asf=1/T
Rewriting given equation in the form as in equation (2) we get
y(x,t)=5.5sin 2pi(0.010x-2.0t)
Comparing with (2)
1/lambda=0.010=>lambda=1/0.010=>lambda=100cm
1/T=2.0=>f=2.0Hz