Question #95e4b

2 Answers

This is
Simple harmonic motion (I know u know this ),
For simple harmonic motion Equation is written as
y=A sin(kx-omegat)
k=Force constant,
AS , pi is multiplied inside.
k=0.020pi
omega=4.0(pi)

k=(2pi)/Lambda
So substitute here get lambda

And ,
frequency=c/lambda
c is speed of light=3*10^8
Intensity=[Power]/area
Intensity is inversely proportional to r^2
So,
Intensity=1/r^2
So,
divide both of them i.e as 45 and ant 90,
2.5/I=(90/45)^2 here I we have to find

Sep 11, 2017

Given equation represents a transverse wave with general equation as

y(x,t)=Asin ((2pi)/lambda)(x-vt) .......(1)
where A is maximum amplitude, lambda is wavelength and v wave velocity. Also -vt implies velocity in +x direction

It also represents Traveling Wave Solution for an ideal string.

it's equivalent form can be written as

y(x,t)=Asin 2pi(x/lambda-t/T) ........(2)
where T is time period and related to frequency as f=1/T

Rewriting given equation in the form as in equation (2) we get

y(x,t)=5.5sin 2pi(0.010x-2.0t)

Comparing with (2)

1/lambda=0.010=>lambda=1/0.010=>lambda=100cm
1/T=2.0=>f=2.0Hz