Question

Is this equation `2Al + 3NiB _ { 2} -> AlB r _ { 3} + 3N _ { i }` balanced?

Answer 1

No.

Explanation:

No.

A balanced equation displays an equal amount of atoms of each element on both sides of the yield arrow.

From what you gave us/me, there are:

• `2` `Al` atoms on the reactant's side, but only `1` on the product's.
• an equal amount of `Ni` atoms, with `3` atoms on each side... unless the product's `Ni` is not a typo and is supposed to be `N_"i"`.
• `2` `Br` atoms on the reactant's side and `3` on the product's... unless it's supposed to be `B` (boron).

In order to balance this equation, we have to play around with the coefficients so that each atom on the reactant's is equal to the to product's.

You should get this:

`2Al + 3NiBr_"2" -> 2AlBr_"3" + 3Ni`

Now if we look at this equation, there are an equal amount of every atom on both sides of the yield arrow.

Hope this helps :)