Question

Question #6e2a4

Answer 1

`[Ne]3s^2 3p^6`

Explanation:

I can only assume you mean electron configuration, so forgive if I'm wrong.

When condensing an electron configuration, you simply go back to the last noble gas and add your orbitals from there. For example, a calcium atom, electron configuration `1s^2 2s^2 2p^6 3s^2 3p^6 4s^2`, has condensed configuration `[Ar]4s^2`, which is much easier to write and read.

The `Ca^(2+)` ion is a calcium atom minus two electrons, and thus has electron configuration `1s^2 2s^2 2p^6 3s^2 3p^6`, which is the same as argon, `Ar`. You cannot simply write `[Ar]`, however. Instead, you go back to the last noble gas, which is neon, `[Ne]`. This gives a condensed configuration of `[Ne]3s^2 3p^6`.