What is the equation of the line that passes through points (\frac { 1} { 2} ,\frac { 1} { 3} ) and ( \frac { 1} { 14} ,\frac { 11} { 14} )?

1 Answer
Sep 29, 2017

y+19/18x-31/36=0

Explanation:

Finding the slope
m=(y_2-y_1)/(x_2-x_1)

=((11/14)-(1/3))/((1/14)-(1/2))=(-19)/18

Now, using the point slope formula with point (1/2, 1/3),
y-y_1=m(x-x_1)

y-(1/3)=(-19)/18(x-1/2)

y+19/18x+(-1/3-19/36)=0

y+19/18x-31/36=0... Check it out here
graph{y+19/18x-31/36=0 [-10, 10, -5, 5]}