How do you solve #4s - 7= 8s#?

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Answer 1 · 2017-09-29T18:54:13

See a solution process below:

First, subtract #color(red)(4s)# from each side of the equation to isolate the #s# term while keeping the equation balanced:

#-color(red)(4s) + 4s - 7 = -color(red)(4s) + 8s#

#0 - 7 = (-color(red)(4) + 8)s#

#-7 = 4s#

Now, divide each side of the equation by #color(red)(4)# to solve for #s# while keeping the equation balanced:

#-7/color(red)(4) = (4s)/color(red)(4)#

#-7/4 = (color(red)(cancel(color(black)(4)))s)/cancel(color(red)(4))#

#-7/4 = s#

#s = -7/4#