Question

How do you find the LCD for `2x(x-1) , x^2- 1 , 4`?

Answer 1

`LCD=4x(x^2-1)`

Explanation:

The given terms are
`2x(x-1), (x^2-1),4`
Factors of each term :
`2x(x-1)=2*x*(x-1)`
`(x^2-1)=(x+1)(x-1)`
`4`
`LCD=4*(x+1)(x-1)*x=4x(x^2-1)`