Question

Question #3f803

Answer 1

`x=-2`

Explanation:

`-3x-15=3x-3` by removing brackets in both sides.
`-15+3=3x+3x` by bringing x terms to one side and constant the other side.
`6x=-12` or `x=-(12/6)=-2`

Answer 2

`x=-2`

Explanation:

`"using the "color(blue)"distributive property"`

`•color(white)(x)a(b+c)=ab+ac`

`"apply this concept to the brackets on both sides of the"`
`"equation"`

`rArr-3x-15=3x-3`

`"collecting terms in x on the left side and numeric values"`
`"on the right side"`

`"subtract 3x from both sides"`

`-3xcolor(red)(-3x)-15=cancel(3x)cancel(-3x)-3`

`rArr-6x-15=-3`

`"add 15 to both sides"`

`-6xcancel(-15)cancel(+15)=-3color(red)(+15)`

`rArr-6x=12`

`"divide both sides by "-6`

`(cancel(-6) x)/cancel(-6)=12/(-6)`

`rArrx=-2`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`"left "=(-3xx3)=-9`

`"right "=(-3xx3)=-9`

`rArrx=-2" is the solution"`

Answer 3

`x=-2`

Explanation:

If we look at just `-3(x+5)` for now, you have to multiply each part in the parenthesis by what it's all being multiplied by. In this case, when we multiply `x` by `-3`, it's `-3x`, then the `5` times the same is `-15`.

So the first side is now

`-3x-15`

We do the same for the other side resulting in

`3x-3`

So now we have

`-3x-15=3x-3`

We get all the `x`'s together by adding `3x` to both sides to remove it from the left and adding to the right resulting in

`-15=6x-3`

We then add `3` to both sides to remove it from the right and add to the left resulting in

`-12=6x`

Now we can solve for `x` by dividing both sides by `6`, resulting in

`-2=x`