Question #183f1

2 Answers
chandramohanPanakkal
Oct 10, 2017

There is no palace where there is no G.

Explanation:

As distance increases the value of G become very small.
THe distance means from the center of mass,

Aditya Banerjee.
Oct 10, 2017

Here's the reason.

Explanation:

First of all you need to be clear of three cases:

(1) gravitational acceleration at the surface of earth.

(2) gravitational acceleration at an altitude above the earth's surface.

(3) gravitational acceleration at a depth of below the earth's surface.

Now let us consider the following:

**#M=# mass of earth.

#m=# mass of an object.

#g=# acceleration due to gravity.

#G=# universal gravitational constant.

#R=# radius of earth being considered as a perfect sphere.

#h=# altitude.

#d=# depth.

#g_h=# gravitational acceleration at an altitude #h#.

#g_d=# gravitational acceleration at a depth #d#.**

Case 1 #rarr#

#g=(GM)/R^2#.

Case 2 #rarr#

#g_h=g(1+h/R)^(-2)#.

Case 3 #rarr#

#g_d=g(1-d/R)#.

Now, let us come to your doubt.

If an object is placed at the centre #(C)# of the earth, it lies at a depth of #R# distance apart from the surface of the earth.

At this situation, #d=R#.

#:.g_d=g(1-d/R)#

#:.g_C=g(1-R/R)#

#:.g_C=g(1-1)#

#:.g_C=0#.

Hence, at the centre of the earth there is no acceleration due to gravity and hence no gravitational force is experienced by any object.

Hope it Helps:)

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