Question

How do you simplify `\frac { 10h ^ { 2} - 17h + 3} { 3h - 3} \cdot \frac { h - 1} { 10h ^ { 2} - 17h + 3}`?

Answer 1

`(10h^2-17h+3)/(3h-3)*(h-1)/(10h^2-17h+3)=1/3`

Explanation:

`(10h^2-17h+3)/(3h-3)*(h-1)/(10h^2-17h+3)=( cancel((10h^2-17h+3))cancel((h-1)))/(3cancel((h-1))cancel((10h^2-17h+3)))=1/3`

Answer 2

`1/3`

Explanation:

...when multiplying terms like this, where you have numerators and denominators, any factor appearing in both a numerator and denominator can be cancelled out.

So right away, your polynomial `10h^2-17h+3`, which appears in the numerator of one term and denominator of the other, cancels out. This leaves:

`(h-1)/(3h-3)`

...and you can factor out a 3 from the denominator:

`(h-1)/(3(h-1))`

...and once again you have a term `(h-1)` appearing in both numerator & denominator, which cancels out, leaving

`1/3`

GOOD LUCK