In a three-digit number, the second and third digits are the same. The first digit is 4 more than the sum of the second and third digits. What would be the expression in simplest form for the total sum of all three digits?

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Answer 1 · 2017-10-11T18:06:55

Let's have a look.

Let the first digit be #x#.
& the second & third digit be #y#.

Hence, the three digit number is #xyy#.

Given, #x=4+(y+y)#.

#:.x=2y+4#......(1).

Hence the sum of all the digits is #rarr#

#=x+y+y#

#=2y+4+2y# #larr# From (1).

#=4y+4#

#=4(y+1)#.

Hence, the sum of the three digits in terms of second & third digit is #4(y+1)#. (Answer).

Hope it Helps:)