Question

Question #fbbe2

Answer 1

I would say C)

Explanation:

When is compressed or elongated it will have Elastic Potential Energy stored in its structure and ready to, say, do work in pushing or pulling an object.
At a certain height from the ground it will have Gravitational Potential Energy with respect to the ground so that in falling it will do work.

Answer 2

At it's natural length .

Explanation:

Potential energy of the spring is minimum when it is in natural length .

Let us imagine a spring of natural length L .Let the elastic

potential energy of the spring be P. We are extending (or

compressing) that spring to length x such that it's length become

L+x (if compressed L-x).

Now the elastic potential energy of the spring is directly proportional to the square of the extended length.

`P alpha x^2`

`P=a*x^2`

where a is the constant of proportionality

which is equal to `k/2` (k is the spring constant it depends on the material of the spring )

Therefore elastic potential energy can be given by the expression

`P=1/2*kx^2`

So when we compress or extended there elastic potential enrgy increases.

If we do not compress or extend the spring the value of x will be zero therefore the potential stored it in will be zero .

Gravitational potential energy:

`F=m*g*h`

F is the Gravitational potential energy,

m is the mass of the spring

g is the acceleration due to gravity ,

h is the height at which the spring is placed .

Therefore at a height spring will definitely have some potential energy .